2x^2+100x+1200=0

Solution for 2x^2+100x+1200=0 equation:

2x^2+100x+1200=0

a = 2; b = 100; c = +1200;
Δ = b2-4ac
Δ = 1002-4·2·1200
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-20}{2*2}=\frac{-120}{4}
=-30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+20}{2*2}=\frac{-80}{4}
=-20
$